# How do you find the vertex, axis of symmetry and intercepts of #f(x)=3x^2+x-3#?

##### 1 Answer

Feb 15, 2016

f(x) = 3x^2 + x - 3

#### Explanation:

x-coordinate of vertex, or axis of symmetry:

y-coordinate of vertex:

To find y-intercept, make x = 0 --> y = -3

To find x-intercepts, make y = 0 and solve the quadratic equation

There are 2 real roots, or two x-intercepts: